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CSIR UGC NET Dec15 Q.7

Vishnu Mestry Tuesday, 11 October 2016 No Comments
Identify the complex ions in the sequential order when ferroin is used as an indicator in the titration of iron(II) with potassium dichromate. (phen = 1, 10- phenathroline) 
A. [Fe(phen)3] 2+ and [Fe(phen)3] 3+ 
B. [Fe(phen)3] 3+ and [Fe(phen)3] 2+ 
C. [Fe(CN)6] 4- and [Fe(CN)6] 3- 
D. [Fe(CN)6] 3- and [Fe(CN)6] 4- 

Soln: A. [Fe(phen)3] 2+ and [Fe(phen)3] 3+ 

Expln:
Ferroin is the chemical compound with the formula [Fe(o-phen)3]SO4, where o-phen is an abbreviation for 1,10-phenanthroline, a bidentate ligand.


The most important application of dichromate is in its reaction with iron(II) in which it is often preferred to permanganate. 
The relevant half reaction is :
Fe2+ → Fe3+ + e-     E° = -0.77 V
and the total reaction is:
Cr2O72- + 6 Fe2+ + 14H+ → 2Cr3+ + 6 Fe3+ + 7H2O     E° = 0.56 V 

Therefore, a sharp colour change from red to blue occurs on oxidation of the complex. 
[Ph3Fe]2+ → [Ph3Fe]3+

The indicator is prepared by mixing equivalent quantities of iron(II) sulphate and 1, 10- phananthroline. The resulting Fe(II) complex sulphate is called Ferroin. The Fe(III) complex sulphate is called ferrin. The color of ferroin is so much more intense than that of ferrin.

(Reference: Harris, D. C. Quantitative Chemical Analysis (4th ed.). New York, NY: W. H. Freeman. ISBN 0-7167-2508-8.)
http://wwwchem.uwimona.edu.jm/lab_manuals/c10expt31.html
Vishnu Mestry

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